3x^2-x-4 how to split the middle term
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Answered by
1
3x^2+3x-4x-4
3x(x+1)-4(x+1)
(3x-4)(x+1)
x=4/3 & x=(-1)
3x(x+1)-4(x+1)
(3x-4)(x+1)
x=4/3 & x=(-1)
Answered by
1
3x^2 - x - 4
= 3x^2-4x+3x-4
= x(3x-4)+1(3x-4)
= (x+1)(3x-4)
(x+1) =0 (3x-4)=0
x=-1 x = 4/3
hope it helps you...
= 3x^2-4x+3x-4
= x(3x-4)+1(3x-4)
= (x+1)(3x-4)
(x+1) =0 (3x-4)=0
x=-1 x = 4/3
hope it helps you...
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