Math, asked by clpm, 1 year ago

3x^2-x+7 find the zeroes

Answers

Answered by Anonymous
1
3x^2 - x + 7 = 0
D = b^2 - 4ac
D = (-1)^2 - (4×3×7)
D = 1 - 84
D = -83
As the discriminant has negative sign (-) , the roots of this quadratic equation are imaginary roots and are not real roots.
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