3x^2-x+k=0
FIND THE VALUE OF K
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Answer:
3x²-x+k=0
b²-4ac=0 (if x has equal roots)
a=3, b=1,c=k
1²-4(3)(k)=0
1-12k=0
1=12k
1/12=k.
Step-by-step explanation:
so the Value of k is 1/12
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