Question

3x+25-x=5x+12 solve the following​

Answer 1

Answer:

3x+25-x=5x+12

3x-x -5x = 12-25

-3x = -13

$x = \frac{ \cancel - 13}{ \cancel- 3}$

x= 13/3

Answer 2

Let's solve your equation step-by-step.

3x + 25 - x = 5x + 12

Step 1: Combine like terms and solve in the LHS.

⇒ 3x + 25 - x = 5x + 12

⇒ 3x - x + 25 = 5x + 12

⇒ 2x + 25 = 5x + 12

Step 2: Subtract 2x from both sides of the equation.

⇒ 2x + 25 - 2x = 5x + 12 - 2x

⇒ 2x - 2x + 25 = 5x - 2x + 12

⇒ 25 = 3x + 12

Step 3: Flip the equation.

⇒ 25 = 3x + 12

⇒ 3x + 12 = 25

Step 4: Subtract 12 from both sides of the equation.

⇒ 3x + 12 - 12 = 25 - 12

⇒ 3x = 13

Step 5: Divide 3 from both sides of the equation.

⇒ $\dfrac{3x}{3} =\dfrac{13}{3}$

⇒ $x = \dfrac{13}{3}$

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Verification for the value of 'x'

⇒ 3x + 25 - x = 5x + 12

⇒ $3(\dfrac{13}{3}) + 25 - \dfrac{13}{3} = 5(\dfrac{13}{3}) + 12$

⇒ $13 + 25 - \dfrac{13}{3} = \dfrac{65}{3} + 12$

⇒ $\dfrac{13\times 3}{1\times 3} + \dfrac{25\times 3 }{1\times 3} - \dfrac{13}{3} = \dfrac{65}{3} + \dfrac{12\times 3}{1\times 3}$

⇒ $\dfrac{39}{3} + \dfrac{75 }{3} - \dfrac{13}{3} = \dfrac{65}{3} + \dfrac{36}{3}$

⇒ $\dfrac{114}{3} - \dfrac{13}{3} = \dfrac{101}{3}$

⇒ $\dfrac{101}{3} = \dfrac{101}{3}$

∴ LHS = RHS

$\bf \therefore x = \frac{13}{3 } \ in \ the \ equation \ \rightarrow\ 3x + 25-x=5x+12$

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