3x+2ky=2 ಮತ್ತು 2x+5y+1=0 ಜೋಡಿ ಸಮೀಕರಣಗಳು ಪರಸ್ಪರ ಸಮಾಂತರವಾಗಿದ್ದರೆ 'k'ಯ ಬೆಲೆ
Answers
Answered by
0
Explanation:
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Answered by
3
Answer:
Suppose that we have to parallel lines a
1
x+b
1
y+c
1
=0 & a
2
x+b
2
y+c
2
=0 then,ratio of coefficient of x and y are equal i.e.
a
2
a
1
=
b
2
b
1
.
Now, according to given equations
3x+2ky=2
2x+5y+1=0
compairing coeffient of x& y and applying rule,
2
3
=
5
2k
⇒4k=15
So value of k=
4
15
.
Explanation:
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