Question

-3x[{-(-2x-3x)(9x-2)}]=32
Solve this equation.
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Answer 1

Answer:

$-3x[-((-2x-3x)(9x-2))]=32 \\ -3x[-(( - 5x)(9x - 2))]=32 \\ -3x[-( - 45x + 10)]=32 \\ -3x(45x - 10)=32 \\ - 135 {x}^{2} + 30x = 32 \\ - 135 {x}^{2} + 30x - 32 \\ - 1(- 135 {x}^{2} + 30x - 32) \\ 135 {x}^{2} - 30x + 32$