Question

(3x + 2x²+ 4x³) ÷ (x -4)​

Answer 1

Answer:

$\frac{4 {x}^{3} + 2 {x}^{2} + 3x }{x - 4} \\ = \frac{x(4 {x}^{2} + 2x + 3 )}{x - 4}$

Answer 2

Step-by-step explanation:

$\frac{4 {x}^{3} + 2 {x}^{2} + 3x }{x - 4}$

$\frac{x(4 {x}^{2} + 2x + 3) }{x - 4}$

$= = = =$