3x+2y=0 and x+3y=7.Find the value of x and y using elimination method
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eq (2)×3
3x+9y=21...... eq (3)
eq (1)-(2)
-7y=-21
y=3
put ek(1)
3x-3=0
3x=3
x=1
x=1,and y=3
is your answer
3x+9y=21...... eq (3)
eq (1)-(2)
-7y=-21
y=3
put ek(1)
3x-3=0
3x=3
x=1
x=1,and y=3
is your answer
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