Math, asked by ankitpal2170, 13 hours ago

3x-2y=0 and y=48/13 find x​

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Answered by sumit70226
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Answered by uttambera538
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3x - 2y = 0

y = 48/13

2y = \frac{48}{13} × 2 = 3x

2y = \frac{96}{13} = 3x

3x = \frac{96}{13}

x = 3x/3 = 96/13/3

x = 32/3

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