Math, asked by dominicluiz425, 10 months ago

3x-2y=1 2x-3y=-6 by elimination method​

Answers

Answered by Mora22
1

Answer:

x=3,y=4

Step-by-step explanation:

3x-2y=1--->equation 1

2x-3y=-6--->equation 2

Multiply equation 1 with 2 and equation 2 with 3

Equation 1 becomes 6x-4y=2

let it be equation 3

Equation 2 becomes 6x-9y=-18

let it be equation 4

subtract equation 4 from 3

we get 5y=20

y=4

and by substituting y value we get x =3

Therefore x,y are 3,4.

Answered by jahnavijahnavi244
0

Step-by-step explanation:

1)2x+3y=7

let 3y=7-2x

let x=1

3y=7-2(1)

3y=7-2

3y=5

y=5/3 (1,5/3)

let x=2

3y=7-2(2)

3y=7-4

3y=3

y=1 (2,1) and so on

2)3x-2y=3

let x=1

-2y=3-3(1)

-2y=3-3

y=0 (1,0)

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