3x+2y=1 and (2k+1)x+(k+2)y=k-2
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Answer: i hope this will help please put me as brainliest
Explanation:
a_1x+b_1y=c_1
a_2x+b_2y=c_2 have solution, then a_1b_2-a_2b_1\neq0
Given equations are
3x + 2y=1
(3k - 1) X + (2k - 1) y = 2k + 1
Now,
a_1b_2-a_2b_1
=3(2k-1)-(3k-1)2
=6k-3-6k+2
=-1\neq0
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