3x - 2y
1
tim
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x + 3y =
;
2
3
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SOLUTION:-»
Let L^1 and L^2 be the lines passing through the point (2, 3) and perpendicular to the lines 3x + 2y - 1 = 0 and x - 3y + 2 = 0 respectively.
2 be the lines passing through the point (2, 3) and perpendicular to the lines 3x + 2y - 1 = 0 and x - 3y + 2 = 0 respectively.Slopes of the lines 3x + 2y - 1 = 0 and x - 3y + 2 = 0 are -32 and -1-3=13 respectively.
Explanation:
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