3x +2y= 11
2x-3y+10= 0
elimination by substitution method
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3x+2y=11 - - - - -(I)
2x-3y+10=0 i.e 2x-3y=-10- - - - -(ii) Multiplying 2 in eq (ii) and 3 in eq(i) we obtain that =9x+6y=33---(iii) & 4x-6y=-20 -----(IV) Now by adding eq (iii) and eq (IV) we obtain that 13x=13 ,x=13/13=1 -----(v) Now by substituting the value of x in eq (I) we obtain that 3+2y=11 =>2y=11-3=8,y=8/2=4(mark it as brainliest then I will follow you and will mark your answer as brainliest when I will ask questions and you will give the answer.)
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