3x + 2y = 11 ; 2x + 3y = 4 by substition method
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1
Answer:
Step-by-step explanation:
Secondary School Math 5+3 pts
Solve the 2x-y=5 ,3x+2y=11 by substitional method
Report by Sumanth176829 07.08.2018
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choudharigandharv
ChoudharigandharvHelping Hand
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buhaha678
Buhaha678Helping Hand
2x-y=5
-y=5-2x
y= -5+2x
substitute y
3x +2(-5-2x)=11
3x-10+4x=11
7x=11+10
7x=21
x=3
y= -5+2(3)
y=1
Answered by
0
Answer:
y = -2
x= 5.
Step-by-step explanation:
let ,3x+2y=11 as equation 1 and
2x+3y=12 as equation 2.
eq-1×2=6x+4y=22
eq-2×3=6x+9y=12
(-) (-) (-)
0-5y=10
y=-2.
Now, substitute y=2 in eq 2.
2x+3y=4
2x+3(-2)=4
2x-6=4
2x=4+6
2x=10
x=5.
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