Question

3x+2y=11;2x+3y=4 substitution​

Answer 1

$3x + 2y = 11 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - - -(i) \\ 2x + 3y = 4\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - - -(ii)$

$From \: \: equation \: (i), \\ \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{11 - 2y}{3} \: \: \: \: \: \: \: \: - - - (iii)$

Now,

${ \text{Putting \:equation\:(iii)\: in \:equation\:(ii),\:we\:get, }}$

$2( \frac{11 - 2y}{3}) + 3y = 4 \\ \\ \frac{22 - 4y}{3} + 3y = 4 \\ \\ \frac{22 - 4y + 9y}{3} = 4 \\ \\ 22 + 5y = 12 \\ 5y = 12 - 22 \\ 5y = - 10 \\ { \red{{y = \frac{ - 10}{5} = 2}}}$

Again,

${ \text{Putting value of y in equation (iii), we get,}}$

$x = \frac{11 - 2y}{3} \\ \\ \: \: = \frac{11 - 2( - 2)}{3} \\ \\ \: \: = \frac{11 + 4}{3} = { \red{\frac{15}{3} = {5}}}$

Therefore,

${ \text {\huge{ \red{Value of x is 5 \& Value of y is -2}}}}$

Answer 2

Answer:

Step-by-step explanation: