Question

3x+2y=12 and xy=6find value of 9xsquare+4y square

Answer 1

Answer:

72

Step-by-step explanation:

Solve this using (a+b)^2=a^2+b^2+2ab

Let a be 3x

Let b be 2y

(3x+2y)^2=(3x) ^2+(2y) ^2+2*3x*2y

12^2=9x^2+4y^2+12*6

144=9x^2+4y^2+72

9x^2+4y^2=144-72

=72=Answer

Answer 2

Step-by-step explanation:

3x+2y=12

XY=6

3x+2y=12

squaring both sides

(3x+2y)²=(12)²

9x²+4y²+2(3x)(2y)=144

9x²+4y²+12xy=144

9x²+4y²+12(6)=144

9x²+4y²+72=144

9x²+4y²=144-72

9x²+4y²=72