Question

3x+2y=12,xy=6 find value 9x2+4y2=?​

Answer 1

Answer:

72 is the given for the given problem

Answer 2

Step-by-step explanation:

$3x + 2y = 12 \: \: \: \: \: \: \: \: eqn1 \\ xy = 6 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: eqn2\\ find = 9 { x }^{2} + 4 {y}^{2} \\ \\ from1 \\ 3x = 12 - 2y \\ x = \frac{12 - 2y}{3 } \\ put \: into \: eqn2 \\ xy = 6 \\ \frac{(12 - 2y)}{3} \times( y) = 6 \\ 12y - 2 {y }^{2} = 18 \\ 2 {y}^{2} - 12y + 18 \\ 2 {y}^{2} - (6 + 6)y + 18 = 0 \\ 2 {y}^{2} - 6y - 6y + 18 = 0 \\ 2y(y - 3) + 6(y - 3) \\ (2y + 6)(y - 3) \\ 2y = - 6 \\ y = - 3 \\ y = 3$