3x+2y=12and xy=6 find x+1÷x
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Answer:
Given,
xy=6 then,
x=6/y-----equation 1
now,
substitute x=6/y in 3x+2y=12 (by substitution method)
3(6/y)+2y=12
18/y+2y=12
18+2ysquare/y=12
18+2ysquare=12y
2ysquare-12y+18=0
(after taking 2 common)
ysquare-6y+9=0
ysquare-3y-3y+9=0
y(y-3)-3(y-3)=0
(y-3) (y-3)=p
y=3,3
substitute y=3 in equation 1
x=6/3
x=2
then, we should find x+1÷x
2+1÷2
3÷2
therefore the answer is 3/2
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