Question

3x + 2y = 16 and x-2y= 4 . what is the value of x and y ?​

Answer 1

is it a simultaneous linear equation ?

then I've a answer

3x + 2y = 16 -------- (i)

x - 2y = 4 ------------ (ii)

first eliminate the two equations by its opponent.

meaning multiply the equation (i) by 1

as (x) is equals to 1x... and multiply the equation (ii) with 3....

(3x + 2y = 16) X 1 => 3x + 2y = 16

(x - 2y = 4) X 3 => 3x - 6y = 9

now eliminate the two newly formed equation as you did in algebric

subtraction

in algebraic subtraction....[ (+)became (-)and (-)becomes (+) ]

3x + 2y = 16

3x - 6y = 9.

(-) (+) (-)

___________

4y = 7

3

then y = 7/4 or, y = 1 ----

4

no you have to write this statement...

Putting the value of y into equation (i)

we get,

no put the value of y in the place of y in the equation (i)

and after that do solve...

like :-

3x + 2y= 16

3

or, 3x + 2 x (1 ----) = 16

4

14

or, 3x + ----- = 16

4

3x + 14

or. ------------ = 16

4

12x + 14

or. ------------- = 16

4

12x + 14 16

or. ------------- = -------

4 1

now do cross multiplication

like this

12x + 14 = 64

or. 12x = 64 - 14

or. 12x = 50

50. 1

or. x = ------- => 4 -----

12. 12

then your result is

1 3

x = 4 ----- and y = 1 -----

12 4