Question

3x-2y)^2+24=(3x+2y)^2​

Answer 1

Answer:

(3x-2y)^2+24=(3x+2y)^2

(3x)^2-2*3*x*2*y+(2y)^2

9x^2-12xy+4y^2+24=9x^2+12xy+4y^2

12xy+12xy=24

24*2x*2y=24

24xy=24/4

xy=6/24

xy=1/4

Step-by-step explanation:

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