Math, asked by gsivasankar, 10 months ago

(3x+2y)^2-6(3x-2y)-72

Answers

Answered by anjali4999
6

Answer:

(3x+2y)^2-6(3x-2y)-72

=9x^2+4y^2+12xy-18x+12y-72

=9x^2-18x+4y^2+12y+12xy-72

=9x(x-2)+4y(y+3)+12xy-72

Similar questions