Question

3x + 2y = 24, x + 3y = 3, solve using elimination method​

Answer 1

Ans :-

x= -15/7

y = 57

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Answer 2

$\mathbf \orange{Question}$

3x + 2y = 24, x + 3y = 3, solve using elimination method

$\mathbf \orange{</u></em></strong><strong><em><u>A</u></em></strong><strong><em><u>nswer}$

$\mathbf {system \: of \: linear \: equation \: entered}$

$1 \: \: 3x + 2y = 24$

$2 \: \: x + 3y = 3$

$\mathbf{graphic \: representation \: of \: equation}$

refer to the above attachment...

⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀⠀ ⠀ ⠀⠀⠀ ⠀$\large \mathbb{</u></em></strong><strong><em><u>Main </u></em></strong><strong><em><u>Solution</u></em></strong><strong><em><u>:</u></em></strong><strong><em><u>-</u></em></strong><strong><em><u>}$

$3x + 2y = 24</u></em></strong><strong><em><u>{</u></em></strong><strong><em><u>x1</u></em></strong><strong><em><u>$

$x + 3y = 3</u></em></strong><strong><em><u>{</u></em></strong><strong><em><u>x3</u></em></strong><strong><em><u>$

$3x + 2y = 24 \: \: \: \: \: \: \: \:$

$3x + 3y = 3$

$- \: \: \: - \: \: \: \: \: -$

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$- 7 = 15$

$y = \frac{ - 15}{7}$

$x + 3y = 3$

$x + 3y \frac{( - 15)}{7} = 3$

$x = 3 + \frac{45}{7}$

$x = \frac{21 + 45}{7}$

$x = \frac{66}{7 } \: ans$

$\mathbf{hope \: it \: helps \: u}$