Question

3x+2y=27, xy=6 find the value of 9x²+4y²

Answer 1

${(3x + 2y)}^{2} = {27 }^{2} \\ {9x}^{2} + {4y}^{2} + 12xy = 729 \\ {9x}^{2} + {4y}^{2} = 729 - (12 \times 6) \\ {9x}^{2} + {4y}^{2} = 657$
This may help you..

Answer 2

$3x + 2y = 27 \\ xy = 6 \\ {9x}^{2} + {4y}^{2} \: can \: also \: be \: written \: as \: {(3x + 2y)}^{2} \\ {(3x + 2y)}^{2} = {(3x)}^{2} + {(2y)}^{2} + 2(3x)(2y) \\ = {(27)}^{2} = {9x}^{2} + {4y}^{2} + 36 \\ = 729 - 36 = {9x}^{2} + {4y}^{2} \\ \\ therefore \: {9x}^{2} + {4y}^{2} = 693$
your answer is 693 and method is given above.If it satisfies you then please mark my answer as brainliest ☺️