3x-2y=3 , 2x+y=16
find the values of
detominants in the given
equations.
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Answer:
3x-2y=3
multiply 2 on both sides
6x-4y=6( equation-1)
2x+y=16
multiply 3 on both sides
6x+3y=48(equation-2)
subtracting equation 1 from 2
6x+3y=48
(-)6x-4y=6
__________
7y=42
y=6
3x-2y=3
substitute y value
3x-2(6)=3
3x-12=3
3x=3+12
3x=15
x=5
x=5,y=6
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