Math, asked by Michael1john, 3 days ago

3x - 2y =3 ; 4x +5y = 50

Answers

Answered by MrImpeccable
22

ANSWER:

TO SOLVE:

  • 3x - 2y = 3
  • 4x + 5y = 50

SOLUTION:

There are many methods of solving pair of linear equations. The most common are substitution method and elimination method.

Method 1: Substitution Method

:\longrightarrow\sf{3x - 2y = 3----(1)}\\\\:\longrightarrow\sf{4x + 5y = 50}\\\\:\implies\sf{4x=50-5y}\\\\:\implies\sf{x=\dfrac{50-5y}{4}----(2)}\\\\\text{\sf{Putting (2) in (1)}}\\\\:\implies\sf{3\left(\dfrac{50-5y}{4}\right) - 2y = 3}\\\\:\implies\sf{\dfrac{150-15y}{4} - 2y = 3}\\\\:\implies\sf{\dfrac{150-15y-8y}{4}=3}\\\\:\implies\sf{150-23y=12}\\\\:\implies\sf{23y=150-12}\\\\:\implies\sf{23y=138}\\\\:\implies\sf{y=6}

:\implies\sf{x=\dfrac{50-5y}{4}=\dfrac{50-5(6)}{4}=\dfrac{50-30}{4}=\dfrac{20}{4}}\\\\:\implies\sf{x=5}\\\\\text{\sf{So,}}\\\\\bf{:\implies x=5\:\:and\:\:y=6}

Method 2: Elimination Method

:\longrightarrow\sf{3x-2y=3----(3)}\\\\:\longrightarrow\sf{4x+5y=50----(4)}\\\\\text{\sf{Multiplying equation (3) with 5 \& (4) with 2}}\\\\:\implies\sf{15x-10y=15----(5)}\\\\:\implies\sf{8x+10y=100----(6)}\\\\\text{\sf{This made the magnitude of coefficient of y same in both equations}}\\\\\text{\sf{Due to different signs, we add (5) \& (6)}}\\\\:\implies\sf{(15x-10y)+(8x+10y)=15+100}\\\\:\implies\sf{15x-10y+8x+10y=115}\\\\:\implies\sf{23x=115}\\\\:\implies\sf{x=5}\\\\\text{\sf{Putting value of x in (6)}}

:\implies\sf{8(5)+10y=100}\\\\:\implies\sf{40+10y=100}\\\\:\implies\sf{10y=100-40}\\\\:\implies\sf{10y=60}\\\\:\implies\sf{y=6}\\\\\text{\sf{So,}}\\\\\bf{:\implies x=5\:\:and\:\:y=6}

LEARN MORE:

  • In substitution method, we calculate one variable in terms of the other and substitute it in the other equation.
  • In elimination method, we eliminate one variable by either adding or subtracting the equations and then putting that value in one of the equation to get value of the other variable.
Answered by Anonymous
24

\huge{\dag\:{\underline{\boxed{\mathfrak{\purple{Answer}}}}}}

Let us solve this problem by Substitution Method.

3x - 2y =3------(1)

4x +5y = 50-----(2)

_______________

Let us take equation (1) 3x - 2y =3

Now make x alone = 3 + 2y /3

➦ So here value of x is 3 + 2y /3

-----------------------

Now substitute this value of x in eq(2).

4x +5y = 50

4 ( 3 + 2y /3) + 5y = 50

12 + 8y + 15y = 150

23y = 138

➦ y = 6

  • So here we got value of y as 6.

________________

Now let us substitute this value of y in eq(1).

3x - 2y =3

3x - 2(6) = 3

3x = 12 +3

x = 15/3

➦ x = 5

  • So here we got value of x as 5.

-------------------------

Verification;

  • Let us put the value of x and y in both the equations.

Equation 1:-

  • 3x - 2y =3
  • 3(5) - 2(6) = 3
  • 15 - 12 = 3
  • 3 = 3
  • LHS = RHS

Equation 2;

  • 4x +5y = 50
  • 4(5) - 5(6) = 50
  • 20 + 30 = 50
  • 50 = 50
  • LHS = RHS.

___________________

Hence value of x is 5 and y is 6.

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