Math, asked by sonakshigarg5151, 9 months ago

√3x-√2y=√3,√5x+√3y=√2 by elimination method

Answers

Answered by alfasingh007
4

Step-by-step explanation:

√3x-√2y=√3.....(1)×√3

√5x+√3y=√2....(2)×√2

now,

3x-√6y=3........(3)

√10x+√6y=2.......(4)

adding eq(3) & (4).....

x(3+√10)=5

x=5/((3+√10)

x=5(√10-3)

on putting the value of x in eq(4)

5√10(√10-3)+√6y=2

50-15√10+√6y=2

√6y=15√10-48

y=(15√10-48)/√6

y=(15√60-48√6)/6

y=(30√15-48√6)/6

y=5√15-8√6

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