3x^2y-3xy+12x-12 factotice
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Answer:
3x^2y−3xy+12x−12
Take out common in all terms,
3xy(x−1)+12(x−1)
(x−1)(3xy+12)
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Answered by
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Hii :)
=> 3x^2 y−3xy+12x−12
Take out common in all terms,
3xy(x−1)+12(x−1)
(x−1)(3xy+12)
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