Math, asked by Saneer7860, 10 months ago

3x^2y-3xy+12x-12.Solve by factorisation method.

Answers

Answered by alokmemane46

0

Answer:

3x2y−3xy+12x−12

Take out 3xy common from first two terms and 12 from last two terms.

3xy(x−1)+12(x−1)

(x−1)(3xy+12)

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