Question

3x+2y=4;2x-3y=7 by substitution method

Answer 1

Hey Mate ✌

Here's your answer friend,

==> 3x + 2y = 4...............[1]

==> 2x - 3y = 7................[2]

From eq(1) we get,

==> y = 4 - 3x/2............[3]

Now by substituting eq(3) in eq(2) we get,

2x -3y = 7

==> 2x - 3[(4 - 3x)/2] = 7

==> 2x + (- 12 + 9x)/2 = 7

==> (4x -12 + 9x)/ 2 = 7

==> 4x - 12 + 9x = 7 X 2

==> 13x - 12 = 14

==> 13x = 14 + 12

==> 13x = 26

==> x = 2

Now by substituting x = 2 in eq (1) we get,

==> 3x + 2y = 4

==> 3(2) + 2y = 4

==> 6 + 2y = 4

==> 2y = 4 - 6

==> 2y = -2

==> y = (-1)

Thus, x = 2 and y = (-1) .

⭐ Hope it helps you ^_^⭐

Answer 2

Hello friends!!

Here is your answer :

$3x + 2y = 4 \: \: \: ......(1)$


$2x - 3y = 7 \: \: \: ......(2)$


From eqⁿ (1)

$2y = 4 - 3x$


$y = \frac{4 - 3x}{2} \: \: \: .....(3)$



Putting the value of y in eqⁿ (2)


$2x - 3y = 7$


$2x - 3( \frac{4 - 3x}{2} ) = 7$



$2x - \frac{12}{2} + \frac{9x}{2} = 7$


$2x - 6 + \frac{9x}{2} = 7$



$\frac{4x + 9x}{2} = 7 + 6$


$\frac{13}{2} x = 13$


$x = 13 \times \frac{2}{13}$


$x = 2$


Putting the value of x in eqⁿ (3)


$y = \frac{4 - 3x}{2}$


$y = \frac{4 - 3(2)}{2}$


$y = \frac{4 - 6}{2}$


$y = \frac{ - 2}{2}$


$y = - 1$



Therefore, x = 2

y = - 1


Hope it helps you..

☺️☺️☺️☺️

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