3x+2y-5=0 and 6x-5y-1 =0 solve it by substitution method
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Answered by
10
Explanation:
x = (5- 2y)/3 . . . . . . . . . (i)
6x-5y-1=0 . . . . . . . . . . . (ii)
SUBSTITUTE VALUE OF EQUATION (i) IN (ii)
6 (5- 2y)/3 - 5y = 1
2(5- 2y) - 5y =1
10 - 4y - 5y =1
-9y = -9
y= -9/-9
y = 1
now, substitute value of y in equation (i)
x= (5-2y)/3
x= (5- 2(1))/3
= (5 - 2)/3
= 3/3
x= 1
Answered by
7
Answer:
hii
Explanation:
by elimination method this is easy
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