3x+2y-5=0, x-3y-9=0 slove this question in method of substitution
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Answered by
0
Answer:
3x + 2y - 5 = 0
or, 3x + 2y = 5 ----1)
x - 3y -9 = 0
or x - 3y = 9 ------- 2)
From 1)
3x + 2y = 5
or, 3x = 5-2y
or, x = 5-2y/3
Putting value of x in 2)
x - 3y = 9
or, 5-2y/3 -3y = 9
or, 5 - 2y -9y = 27
or, 5-11y = 27
or, 11y = -22
or, y = -2
Now putting value of y in 2)
x - 3y = 9
or x -(3.-2) = 9
or, x + 6 = 9
or x = 3
So x = 3 y = -2
Answered by
1
Answer:
x= (5-2y)/3 ... using 1st equation
substitute this in second equation
after solving
x = 3 and y = -2
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