Math, asked by sumanthsingh415, 1 month ago

3x+2y-5=0, x-3y-9=0 slove this question in method of substitution

Answers

Answered by GNOATGAMINGYT
0

Answer:

3x + 2y - 5 = 0

or, 3x + 2y = 5 ----1)

x - 3y -9 = 0

or x - 3y = 9 ------- 2)

From 1)

3x + 2y = 5

or, 3x = 5-2y

or, x = 5-2y/3

Putting value of x in 2)

x - 3y = 9

or, 5-2y/3 -3y = 9

or, 5 - 2y -9y = 27

or, 5-11y = 27

or, 11y = -22

or, y = -2

Now putting value of y in 2)

x - 3y = 9

or x -(3.-2) = 9

or, x + 6 = 9

or x = 3

So x = 3 y = -2

Answered by SXIXS
1

Answer:

x= (5-2y)/3 ... using 1st equation

substitute this in second equation

after solving

x = 3 and y = -2

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