Question

3x-2y=5/2,1/3x+3y=-4/3 solve by cramers rule​

Answer 1

Answer: x=-\dfrac{1}{2},\ y=\dfrac{-1}{2}

Step-by-step explanation:

Given system: 3x-2y=5/2\\\\1/3x+3y=-4/3

Using Cramer rule:

D=\begin{vmatrix}3 & -2\\ 1/3 & 3\end{vmatrix}=\dfrac{29}{3}

D_1=\begin{vmatrix}5/2& -2\\ -4/3 & 3\end{vmatrix}=\dfrac{29}{6}

D_2=\begin{vmatrix}3 & 5/2\\ 1/3 & -4/3\end{vmatrix}=\dfrac{-29}{6}

Now, x=\dfrac{D_1}{D}=\dfrac{\dfrac{29}{6}}{\dfrac{29}{3}}=\dfrac{1}{2}

x=\dfrac{D_2}{D}=\dfrac{\dfrac{-29}{6}}{\dfrac{29}{3}}=\dfrac{-1}{2}

Hence, x=-\dfrac{1}{2},\ y=\dfrac{-1}{2}

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