3x+ 2y = 5; 2x -3y =7 solve
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Answered by
42
(i) 3x + 2y = 5
(ii) 2x - 3y = 7
(i) * 3: 9x + 6y = 15
(ii) * 2: 4x - 6y = 14
(i) + (ii):
9x + 6y + 4x - 6y = 15 + 14
13x = 29
x = 29/13
substituting value of x:
2*29/13 - 3y = 7
58/13 - 7 = 3y
-33/13 = 3y
y = -11/13
(ii) 2x - 3y = 7
(i) * 3: 9x + 6y = 15
(ii) * 2: 4x - 6y = 14
(i) + (ii):
9x + 6y + 4x - 6y = 15 + 14
13x = 29
x = 29/13
substituting value of x:
2*29/13 - 3y = 7
58/13 - 7 = 3y
-33/13 = 3y
y = -11/13
Answered by
44
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Solve 3x + 2y = 5 and 2x - 3y = 7 by elimination method
SOLUTION :-
3x + 2y = 5 ...... (1)
2x - 3y = 7 ....... (2)
We multiply eq (1) with 2 and eq (2) with 3
eq (1) x 2 => 6x + 4y = 10 ...... (3)
eq (2) x 3 => 6x - 9y = 21 ...... (4)
eq (3) - eq (4) by elimination method
6x + 4y - 6x + 9y = 10 - 21
13y = -11
y = -11/13
substitute the value of y in any of the equation to get the value of x
{ I'm substituting it in eq (1) }
3x + 2(-11/13) = 5
3x - 22/13 = 5
3x = 5 + 22/13
3x = 87/13
x = 87/39
x = 29/13
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