Question

3x+ 2y = 5; 2x -3y =7 solve by elimination method

Answer 1

QUESTION :-

Solve 3x + 2y = 5 and 2x - 3y = 7 by elimination method

SOLUTION :-

3x + 2y = 5 ...... (1)

2x - 3y = 7 ....... (2)

We multiply eq (1) with 2 and eq (2) with 3

eq (1) x 2 => 6x + 4y = 10 ...... (3)

eq (2) x 3 => 6x - 9y = 21 ...... (4)

eq (3) - eq (4) by elimination method

6x + 4y - 6x + 9y = 10 - 21

13y = -11

y = -11/13

substitute the value of y in any of the equation to get the value of x

{ I'm substituting it in eq (1) }

3x + 2(-11/13) = 5

3x - 22/13 = 5

3x = 5 + 22/13

3x = 87/13

x = 87/39

x = 29/13

Answer 2

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Solve 3x + 2y = 5 and 2x - 3y = 7 by elimination method

SOLUTION :-

3x + 2y = 5 ...... (1)

2x - 3y = 7 ....... (2)

We multiply eq (1) with 2 and eq (2) with 3

eq (1) x 2 => 6x + 4y = 10 ...... (3)

eq (2) x 3 => 6x - 9y = 21 ...... (4)

eq (3) - eq (4) by elimination method

6x + 4y - 6x + 9y = 10 - 21

13y = -11

y = -11/13

substitute the value of y in any of the equation to get the value of x

{ I'm substituting it in eq (1) }

3x + 2(-11/13) = 5

3x - 22/13 = 5

3x = 5 + 22/13

3x = 87/13

x = 87/39

x = 29/13

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