Math, asked by ajaysai4874, 4 months ago

3x-2y=5
5x-y=3
By substitution method

Answers

Answered by lbtderek
0

Explanation :

=> 3x - 2y = 5 -------- ( 1 )

=> 5x - y = 3 --------- ( 2 )

=> 5x - y = 3

=> 5x = 3 + y

=> x = 3 + y / 5 -------- ( 3 )

Substituting eq ( 3 ) in eq ( 1 )

=> 3 ( 3 + y / 5 ) - 2y = 5

=> 9 + 3y / 5 - 2y = 5

=> 9 + 3y - 10y / 5 = 5

=> 9 - 7y = 5 × 5

=> 9 - 7y = 25

=> - 7y = 16

=> y = - 16 / 7

Substituting value of y in eq ( 3 )

=> x = 3 + ( - 16 / 7 ) / 5

=> x = 3 - 16 / 7 /5

=> x = 21 - 16 / 35

=> x = 5 / 35

=> x = 1 / 7:

Answered by Anonymous
0

3x-2y=5-------------------1st equation.

5x-y=3---------------------2nd equation.

Substitute 1st equation in terms of x

then it becomes-----x= (5+2y)/3

use this value of z in place of x in 2 nd Equation.

then 2nd equation becomes

5×(5+2y)/3 -y=3

as we solve this equation we will get.

(25+10y)/3-y=3

25+7y/3=3

25+7y=9

7y=9-25

7y=-16

y= -16/7

Now finding the value of x

Use the value of y as -16/7

and solve the equation you will get the value of x

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