3x-2y=5,5x-y=3 find by substitution method
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3x-2y=5---eq1
5x-y=3---eq2
from eq2
y=5x-3---eq3
substituting eq3 in eq1
then,
3x-2(5x-3)=5
3x-10x+6=5
-7x+1=0
x=1/7
substituting x value in eq3
then,we get
y=5(1/7)-3
y=(5/7)-3
y=-16/7
if the above solution is wrong please forgive me
I think it is 100% correct
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