Question

3x+2y=5 and 2x-3y=7 by substitution method

Answer 1

Answer:

$3x + 2y = 5.........a \\ 2x - 3y = 7 .........b \\ equation \: \: a \: \times 2 - equation \: \: b \times 3 \\ 6x + 4y = 10 \\ 6x - 9y = 21 \\ 13y = - 11 \\ y = \frac{ - 11}{13} \\ put \: the \: value \: of \: y \: in \: equation \: a \\ 3x + 2( \frac{ - 11}{13} ) = 5 \\ 3x - \frac{22}{13} = 5 \\ 3x = 5 + \frac{22}{13} \\ 3x = \frac{65 + 22}{13} \\ 3x = \frac{87}{13} \\ x = \frac{87}{39}$

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Answer 2

Answer:

3x+2y=5

2x-3y=7

Step-by-step explanation:

From 1st equation,

2y=5-3x

y=5-3x/2

putting the value of y in 2nd equation.

2x-3(5-3x/2)=7

4x-15+9x=14

13x=29

x=29/13

By substituting the value of x in 1 st equation,we get

y=-11/13

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