Question

3x-2y =5 and 5x-3y=13
Do it by substitution method

Answer 1

☆Solution ==》

Answer:-

y= 14

x= 11

Given=》

▪︎ 3x-2y=5

▪︎ 5x-3y=13

Explanation =》

▪︎3x-2y =5

3x=5+2y

x=5+2y/3............(1)

▪︎ 5x-3y=13

putting x= 5+2y/3

$5( \frac{5 + 2y}{3} ) - 3y = 13 \\ = \frac{25 + 10y}{3} - \frac{3y}{1} = 13 \\ \frac{25 + 10y - 9y}{3} = 13 \\ = \frac{25 + y}{3} = 13 \\ = 25 + y = 39 \\ = y = 14$

putting y=14 in eq 1

$\frac{5 + 2y}{3} \\ = \frac{5 + 2 \times 14}{3} \\ = \frac{5 + 28}{3} \\ = x = 11$

So value of x = 11 and y= 14

hope IT HELPs....

Answer 2

Answer: 3x-2y = 5

3x = 5 + 2y

x = 5 + 2y

3

5x - 3y = 13

5(5+2y) - 3y = 13

3

25+10y - 3y = 13

3

25+10y-9y = 13

3

25+y = 13 × 3

y = 39 - 25

y = 14

x = 5+2y

3

x = 5+2(14)

3

x = 5+28

3

x = 33

3

x = 11

So, x = 11 and y = 14.