Math, asked by vallarideodhar, 2 months ago

3x+2y=-5 ; x+4y=-5 by substitution method​

Answers

Answered by tennetiraj86
1

Step-by-step explanation:

Given :-

3x+2y = -5

x+4y = -5

To find :-

The solutions .

Solution :-

Given pair of linear equations in two variables are

3x+2y = -5 ----------(1)

x+4y = -5 ------------(2)

=> x = -5-4y ----------(3)

On substituting the value of x in the equation (1)

3(-5-4y)+2y = -5

=> -15-12y+2y = -5

=> -15-10y = -5

=> -10y = -5+15

=> -10y = 10

=> y = 10/-10

=> y = 1/-1

=> y = -1

Therefore, y = -1

On substituting the value of y in (3) then

x = -5-4(-1)

=> x = -5+4

=> x = -1

Therefore, x = -1

Therefore, Solution = (-1,-1)

Answer :-

The solution of the given pair of linear equations in two variables is (-1,-1)

Check :-

If x = -1, y = -1 then LHS of the given equation

=> 3x+2y

=> 3(-1)+2(-1)

=> -3-2

=> -5

=> RHS

=> LHS = RHS

and

If x = -1 , y = -1 then LHS of the given equation

=> x+4y

=> -1+4(-1)

=> -1-4

=> -5

=> RHS

=> LHS = RHS

Therefore , LHS = RHS is true for the solution (-1,-1)

Verified the given relations in the given problem.

Used Method :-

Substitution method

Answered by krohit68654321
0

Step-by-step explanation:

Step-by-step explanation:

Given :-

3x+2y = -5

x+4y = -5

To find :-

The solutions .

Solution :-

Given pair of linear equations in two variables are

3x+2y = -5 ----------(1)

x+4y = -5 ------------(2)

=> x = -5-4y ----------(3)

On substituting the value of x in the equation (1)

3(-5-4y)+2y = -5

=> -15-12y+2y = -5

=> -15-10y = -5

=> -10y = -5+15

=> -10y = 10

=> y = 10/-10

=> y = 1/-1

=> y = -1

Therefore, y = -1

On substituting the value of y in (3) then

x = -5-4(-1)

=> x = -5+4

=> x = -1

Therefore, x = -1

Therefore, Solution = (-1,-1)

Answer :-

The solution of the given pair of linear equations in two variables is (-1,-1)

Check :-

If x = -1, y = -1 then LHS of the given equation

=> 3x+2y

=> 3(-1)+2(-1)

=> -3-2

=> -5

=> RHS

=> LHS = RHS

and

If x = -1 , y = -1 then LHS of the given equation

=> x+4y

=> -1+4(-1)

=> -1-4

=> -5

=> RHS

=> LHS = RHS

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