Question

3x-2y +6=0 and 6x-4y +8=0​

Answer 1

Answer:

solve by substitution method

3x-2y+6=0(equ.1

6x-4y+8=0(equ.2)

in equ.1

3x-2y+6=0

3x=2y-6

x=2y-6/3(equ3)

putting the value of x in equation2

6(2y-6)/3-4y+8=0

2(2y-6)-4y+8=0

4y-12-4y+8=0

-12+8=0

-4=0

which is false statement

theregor,the equations do not have a common solution

Answer 2

Step-by-step explanation:

3x-2y=6. .....(.eq1)

6x-4y=8.........(eq2)

Mutiply eq1 by 2

6x-4y=12......(eq3)

Add eq1 and eq2

6x-4y=8

6x-4y=12

_______

12x-8y= 20.....(eq4)

Subtract eq1 and eq2

6x-4y=12

6x-4y=8

_______

x - y = 4.....(eq5)

Mutiply eq5 by 8

8x-8y=32......(eq6)

Subtract

8x-8y=32

-

12x-8y=20

_______

-4x. =12

x=12/-4

x= -3

Put x=-3 in eq5

-3-y = 4

-y = 4+3

-y =7

y = -7

The solution is

(x,y)=(-3,-7)

I Hope this answer will help you

Please mark as Brainliest