Question

3x-2y-7=0 and 6x+ky=11=0 have a unique solution of

Answer 1

Heya !!



3X - 2Y - 7 = 0 ----------(1)



And,


6X + KY = 11


6X + KY - 11 = 0 -----------(2)



These equations are of the form A1X+ B1Y + C1 and A2X + B2Y + C2.

Where,



A1 = 3 , B1 = -2 and C1 = -7



And,


A2 = 6 , B2 = K and C2 = -11






Therefore,



A1/A2 = 3/6 = 1/2 , B1/B2 = -2/K and C1/C2 = 7/11.



For unique solution , we must have




A1/A2 # B1/B2 [ Where # stands for not equal]



1/2 # -2/K





K # - 4




Hence,



K has all real values , other than -4.