3x+2y=7, 2x-3y=6 in substitute method
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3
Answer:
multiply 3x+2y=7 by 2 and 2x-3y=6 by 3
we get
6x+4y=14 and 6x-9y=6
by eliminating method ,we get
y =8/13
put value of y in 3x+2y=7
we get value of x
x=25/13
Answered by
0
3x+2y=7........(1)
2x-3y=6........(2)
multiplying (1)×2 ... =6x+4y=14.......(3)
(2)×3.....= 6x-9y =18.... (4)
then solve eqn (3) we get 6x= 14-4y
then substitute the value of 6x in eqn (4)
therefore
y=8/13
and x= 25/13
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