3x+2y=700+5x+3y=1100
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Hey there !!
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3x + 2y = 700 ...(1)
5x + 3y = 1100 ...(2)
From (1)
3x = 700 – 2y
x = ( 700 – 2y ) / 3
Substituting x's value in (2)
5 × ( 700 – 2y ) / 3 + 3y = 1100
3500 – 10y + 9y = 3300
10y – 9y = 3500 – 3300
y = 200
Putting y = 200 in (1)
3x + 2 ( 200 ) = 700
3x + 400 = 700
3x = 700 – 400
3x = 300
x = 300 / 3
x = 100
Thus, values of x and y are 100 and 200 respectively.
____________________________________
Hope my ans.'s satisfactory. (^-^)
____________________________________
3x + 2y = 700 ...(1)
5x + 3y = 1100 ...(2)
From (1)
3x = 700 – 2y
x = ( 700 – 2y ) / 3
Substituting x's value in (2)
5 × ( 700 – 2y ) / 3 + 3y = 1100
3500 – 10y + 9y = 3300
10y – 9y = 3500 – 3300
y = 200
Putting y = 200 in (1)
3x + 2 ( 200 ) = 700
3x + 400 = 700
3x = 700 – 400
3x = 300
x = 300 / 3
x = 100
Thus, values of x and y are 100 and 200 respectively.
____________________________________
Hope my ans.'s satisfactory. (^-^)
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