Question

3x-2y=8, 5x+4y=6 liner equation using matrix
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Answer 1

Answer:

$\large\boxed{y=-1, x=2}$

Step-by-step explanation:

To solve this problem, first you have to find the liner equation of 3x-2y=8 and 5x+4y=6 from left to right numbers. Isolate by the x or y on one side of the equation.

Given:

3x-2y=8 and 5x+4y=6

Linear equation is algebraic equation with constants and variable terms of the highest degree.

Solutions:

First, you have to isolate by the x.

$\displaystyle 3x-2y=8$

Add 2y from both sides.

$\displaystyle 2x-2y+2y=8+2y$

Solve.

$\displaystyle 3x=8+2y$

Secondly, divide by 3 from both sides.

$\displaystyle \frac{3x}{3}=\frac{8}{3}+\frac{2y}{3}$

Solve.

$\displaystyle x=\frac{8+2y}{3}$

You have to subsititute by the x=8+2y/3.

$\displaystyle 5*\frac{8+2y}{3}+4y=6$

Next, isolate by the y.

$\displaystyle 5*\frac{8+2y}{3}+4y=6=\boxed{ y=-1}$

Solve by y=-1.

$\displaystyle x=\frac{8+2(-1)}{3}$

$\displaystyle 2*1=2$

$\displaystyle 8-2=6$

Then, you divide the numbers from left to right.

$\displaystyle \frac{6}{3}$

$\displaystyle 6\div3=\boxed{2}$

$\large\boxed{x=2, y=-1}$

Therefore, the final answer is y=-1, and x=2.