Question

3x+2y=8 and 2x-y=3 solve pair of linear equation by elimination method​

Answer 1

Answer:

3x+2y=8−(1)

2x−3y=1−(2)

Multiplying eqn 1 by 3 and 2 by 2 we get

9x+6y=24−(3)

4x−6y=2−(4)

Adding 2 and 4 we get

(9x+6y)+(4x−6y)=24+2

=13x=26

=x=2

Putting equ x=2 in equ (1)

3x+2y=8

=3×2+2y=8

=6+2y=8

=2y=2

y=1

so,x=2,y=1

Answer 2

The solution of equations 3x+2y=8 and 2x-y=3 are x=2 and y=1.

Given:

• Two linear equations.
• $3x + 2y = 8 \quad \text{and}\quad2x - y = 3$

To find:

• Solution of equations using Elimination method.

Solution:

Concept/method to be used:

Elimination method:

In this method coefficient of one variable turned to be same and eliminate that variable, thus find the value of other.

Step 1:

Let

$3x + 2y = 8 ...eq1$

and

$2x - y = 3...eq2$

Multiply eq2 by 2

$4x - 2y = 6...eq3$

Step 2:

Add both equations 1 and 3.

$3x + 2y = 8 \\ 4x - 2y = 6 \\ - - - - - - \\ 7x = 14 \\ - - - - - -$

or

$x = \frac{14}{7}$

or

$\bf \red{x = 2}$

Step 3:

Put value of x in eq2.

$2(2) - y = 3$

or

$4 - y = 3$

or

$- y = 3 - 4$

or

$\bf \red{y = 1}$

Thus,

Solution of equations are x= 2 and y= 1.

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