3x+2y-k=0, x=2,y=1 find k
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putting ×=2 and y=1 in equation 3x+2y-k=0
3 (2)+2 (2)-k=0
6+4-k=0
10-k=0
-k=-10
k=10
3 (2)+2 (2)-k=0
6+4-k=0
10-k=0
-k=-10
k=10
Nirali19:
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