Question

3x+2y-(k-9)=0 and 9x+6y-12=0. Find the value of k. infinitely many solution​

Answer 1

Answer:

k =13

Step-by-step explanation:

For infinetly many solutions, $\frac{a1}{a2} =\frac{b1}{b2} =\frac{c1}{c2}$

$\frac{3x}{9x} =\frac{2y}{6y} =\frac{k-9}{12}$

$\frac{1}{3} =\frac{1}{3} =\frac{k-9}{12}$

3(k-9) = 12

k-9 = 4

k =13