Question

[3x+2yz]bracket square-(2x-2y-z]brackat square

Answer 1

$(3x+2yz)^2-(2x-2y-z)^2\\ \\ =(9x^2+12xyz+4y^2z^2)-(4x^2+4y^2+z^2-8xy+4yz-4xz)\\ \\ =9x^2+12xyz+4y^2z^2-4x^2-4y^2-z^2+8xy-4yz+4xz\\ \\ =9x^2-4x^2+12xyz+4y^2z^2-4y^2-z^2+8xy-4yz+4xz\\ \\ =5x^2+12xyz+4y^2z^2-4y^2-z^2+8xy-4yz+4xz$