Question

3x (3-2y) + 2 (3 xy + x²)-5 :- SIMPLIFY pls tell fast ​

Answer 1

$\large\sf\underline{Given\::}$

• $\sf\:3x(3-2y) +2(3xy+x^{2}) -5$

‎

‎

$\large\sf\underline{To\::}$

• Simplify the given expression

‎

‎

$\large\sf\underline{Solution\::}$

$\sf\:3x(3-2y) +2(3xy+x^{2}) -5$

‎

• Multiplying the terms and simplifying the brackets

‎

$\sf\implies\:9x-6xy+6xy+2x^{2} -5$

‎

• Solving the like terms by various mathematical operations

‎

$\sf\implies\:9x-\cancel{6xy}+\cancel{6xy}+2x^{2} -5$

$\sf\implies\:9x+2x^{2} -5$

‎

• Arranging the terms so that we can factorise

Let's factorise now !

‎

$\sf\implies\:2x^{2} +9x-5$

‎

• Multiplying 2 and 5 we get 10 . So we need to find such a number whose sum or difference is 9 and whose product gives us 10 .

‎

The two numbers are 10 and 1 and their difference gives the middle term that is 9 whereas their product 10 × 1 = 10 .

‎

‎$\sf\implies\:2x^{2} +(10-1)x-5$

‎

• Multiplying the middle terms

‎

‎$\sf\implies\:2x^{2} +10x-x-5$

‎

• Taking 2x common from first two terms and 1 common from other the other two terms.

‎

‎$\sf\implies\:2x(x+5) -1(x+5)$

$\small{\underline{\boxed{\mathrm\pink{\implies\:(2x-1)(x+5)}}}}$ ★

‎

!! Hope it helps !!