Question

3x^3-ax^2+6x-a is divided by x-a?​

Answer 1

Answer:

Step-by-step explanation:

Here, p(x)=x  3  +ax  2  +6x−a, and the zero of x−a is a

So, p(a)=a  3  +a×a  2  +6×a−a =2a  3 +5a

   So, by the Remainder Theorem, 2a   +5a is the remainder when x  3 +ax  2 +6x−a is divided by x−a.